What are the solutions to the equation -4.9x^2+2.8x-14.5=0 ?

The solutions to the equation -4.9x^2+2.8x-14.5=0 are x= 2/7-i(sqrt(141))/7 ,x= 2/7+i(sqrt(141))/7

Find the zeros of -4.9x^2+2.8x-14.5=0

The zeros of -4.9x^2+2.8x-14.5=0 are x= 2/7-i(sqrt(141))/7 ,x= 2/7+i(sqrt(141))/7

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- 4.9 x^{2} + 2.8 x - 14.5 = 0

x = \frac{2}{7} - i \frac{141}{7}, x = \frac{2}{7} + i \frac{141}{7}

Solution steps

- 4.9 x^{2} + 2.8 x - 14.5 = 0

Multiply both sides by

10

- 49 x^{2} + 28 x - 145 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 ( - 49 ) ( - 145 )}{2 ( - 49 )}

Simplify

2 8^{2} - 4 (- 49) (- 145) : 14141 i

x_{1, 2} = \frac{- 28 \pm 14 141 i}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 28 + 14 141 i}{2 ( - 49 )}, x_{2} = \frac{- 28 - 14 141 i}{2 ( - 49 )}

x = \frac{- 28 + 14 141 i}{2 ( - 49 )} : \frac{2}{7} - i \frac{141}{7}

x = \frac{- 28 - 14 141 i}{2 ( - 49 )} : \frac{2}{7} + i \frac{141}{7}

The solutions to the quadratic equation are:

x = \frac{2}{7} - i \frac{141}{7}, x = \frac{2}{7} + i \frac{141}{7}

- x^{2} - 8 x + 3 = 0

\frac{1}{x + 1} > \frac{2}{x - 1}

ab + ah

30 \cdot \frac{π}{180}

(4 - 6 i)^{2}

What are the solutions to the equation -4.9x^2+2.8x-14.5=0 ?
The solutions to the equation -4.9x^2+2.8x-14.5=0 are x= 2/7-i(sqrt(141))/7 ,x= 2/7+i(sqrt(141))/7
Find the zeros of -4.9x^2+2.8x-14.5=0
The zeros of -4.9x^2+2.8x-14.5=0 are x= 2/7-i(sqrt(141))/7 ,x= 2/7+i(sqrt(141))/7