What are the solutions to the equation 8(4x-1)(x+3)=0 ?

The solutions to the equation 8(4x-1)(x+3)=0 are x= 1/4 ,x=-3

Find the zeros of 8(4x-1)(x+3)=0

The zeros of 8(4x-1)(x+3)=0 are x= 1/4 ,x=-3

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8 (4 x - 1) (x + 3) = 0

x = \frac{1}{4}, x = - 3

Decimal Notation

x = 0.25, x = - 3

Solution steps

8 (4 x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 1 = 0 or x + 3 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 3

y^{2} - 4 y - 2 = 0

2 a^{2} - 8 a + 5 = 0

x^{2} + 7 x + 10 = 0

x^{2} - 20 x + 200 = 0

x^{2} + 8 x - 1 = 0

What are the solutions to the equation 8(4x-1)(x+3)=0 ?
The solutions to the equation 8(4x-1)(x+3)=0 are x= 1/4 ,x=-3
Find the zeros of 8(4x-1)(x+3)=0
The zeros of 8(4x-1)(x+3)=0 are x= 1/4 ,x=-3