What are the solutions to the equation y^2-4y-2=0 ?

The solutions to the equation y^2-4y-2=0 are y=2+sqrt(6),y=2-sqrt(6)

Find the zeros of y^2-4y-2=0

The zeros of y^2-4y-2=0 are y=2+sqrt(6),y=2-sqrt(6)

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y^{2} - 4 y - 2 = 0

y = 2 + 6, y = 2 - 6

Decimal Notation

y = 4.44948 \dots, y = - 0.44948 \dots

Solution steps

y^{2} - 4 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 2) = 26

y_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 1}

y = \frac{- ( - 4 ) + 2 6}{2 \cdot 1} : 2 + 6

y = \frac{- ( - 4 ) - 2 6}{2 \cdot 1} : 2 - 6

The solutions to the quadratic equation are:

y = 2 + 6, y = 2 - 6

2 a^{2} - 8 a + 5 = 0

x^{2} + 7 x + 10 = 0

x^{2} - 20 x + 200 = 0

x^{2} + 8 x - 1 = 0

x^{2} + 17 x + 12 = 0

What are the solutions to the equation y^2-4y-2=0 ?
The solutions to the equation y^2-4y-2=0 are y=2+sqrt(6),y=2-sqrt(6)
Find the zeros of y^2-4y-2=0
The zeros of y^2-4y-2=0 are y=2+sqrt(6),y=2-sqrt(6)