What are the solutions to the equation (x+3)(2x-5)=0 ?

The solutions to the equation (x+3)(2x-5)=0 are x=-3,x= 5/2

Find the zeros of (x+3)(2x-5)=0

The zeros of (x+3)(2x-5)=0 are x=-3,x= 5/2

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(x + 3) (2 x - 5) = 0

x = - 3, x = \frac{5}{2}

Decimal Notation

x = - 3, x = 2.5

Solution steps

(x + 3) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or 2 x - 5 = 0

Solve

x + 3 = 0 : x = - 3

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = - 3, x = \frac{5}{2}

7 x^{2} = 10 x - 3

2 x^{2} - 16 x + 82 = 0

r^{2} + 8 = 0

2 x^{2} - 9 x + 7 = 0

x, (x + y)^{2} = 16

What are the solutions to the equation (x+3)(2x-5)=0 ?
The solutions to the equation (x+3)(2x-5)=0 are x=-3,x= 5/2
Find the zeros of (x+3)(2x-5)=0
The zeros of (x+3)(2x-5)=0 are x=-3,x= 5/2