What are the solutions to the equation r^2+8=0 ?

The solutions to the equation r^2+8=0 are r=2sqrt(2)i,r=-2sqrt(2)i

Find the zeros of r^2+8=0

The zeros of r^2+8=0 are r=2sqrt(2)i,r=-2sqrt(2)i

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r^{2} + 8 = 0

r = 22 i, r = - 22 i

Solution steps

r^{2} + 8 = 0

Move

8

to the right side

r^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 8, r = - - 8

- 8 = 22 i

- - 8 = - 22 i

r = 22 i, r = - 22 i

2 x^{2} - 9 x + 7 = 0

x, (x + y)^{2} = 16

x, 3 z = - y^{2} + x^{2}

- 3 x^{2} + 24 x + 144 = 0

- 3 x^{2} + 2 x - 4 = 0

What are the solutions to the equation r^2+8=0 ?
The solutions to the equation r^2+8=0 are r=2sqrt(2)i,r=-2sqrt(2)i
Find the zeros of r^2+8=0
The zeros of r^2+8=0 are r=2sqrt(2)i,r=-2sqrt(2)i