What are the solutions to the equation (2x+1)x=0 ?

The solutions to the equation (2x+1)x=0 are x=-1/2 ,x=0

Find the zeros of (2x+1)x=0

The zeros of (2x+1)x=0 are x=-1/2 ,x=0

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(2 x + 1) x = 0

x = - \frac{1}{2}, x = 0

Decimal Notation

x = - 0.5, x = 0

Solution steps

(2 x + 1) x = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 0

6 a^{2} - 19 a + 15 = 0

\frac{14}{5} = x + x^{2}

3 y^{2} - 2 y = 0

6 x^{2} = 864

5 x^{2} + 10 x + 15 = 0

What are the solutions to the equation (2x+1)x=0 ?
The solutions to the equation (2x+1)x=0 are x=-1/2 ,x=0
Find the zeros of (2x+1)x=0
The zeros of (2x+1)x=0 are x=-1/2 ,x=0