What are the solutions to the equation x^2-10x=-36 ?

The solutions to the equation x^2-10x=-36 are x=5+sqrt(11)i,x=5-sqrt(11)i

Find the zeros of x^2-10x=-36

The zeros of x^2-10x=-36 are x=5+sqrt(11)i,x=5-sqrt(11)i

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x^{2} - 10 x = - 36

x = 5 + 11 i, x = 5 - 11 i

Solution steps

x^{2} - 10 x = - 36

Move

36

to the left side

x^{2} - 10 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 36 : 211 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 11 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 11 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 11 i}{2 \cdot 1} : 5 + 11 i

x = \frac{- ( - 10 ) - 2 11 i}{2 \cdot 1} : 5 - 11 i

The solutions to the quadratic equation are:

x = 5 + 11 i, x = 5 - 11 i

5 x^{2} + 4 x + 5 = 0

x, x^{2} + 10 x + 25 = 0

x, (x + 2)^{2} - (y + 5)^{2} = 0

x^{2} + 6 x - 216 = 0

9 x^{2} - 12 + 4 = 0

What are the solutions to the equation x^2-10x=-36 ?
The solutions to the equation x^2-10x=-36 are x=5+sqrt(11)i,x=5-sqrt(11)i
Find the zeros of x^2-10x=-36
The zeros of x^2-10x=-36 are x=5+sqrt(11)i,x=5-sqrt(11)i