What are the solutions to the equation 5x^2+4x+5=0 ?

The solutions to the equation 5x^2+4x+5=0 are x=-2/5+i(sqrt(21))/5 ,x=-2/5-i(sqrt(21))/5

Find the zeros of 5x^2+4x+5=0

The zeros of 5x^2+4x+5=0 are x=-2/5+i(sqrt(21))/5 ,x=-2/5-i(sqrt(21))/5

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5 x^{2} + 4 x + 5 = 0

x = - \frac{2}{5} + i \frac{21}{5}, x = - \frac{2}{5} - i \frac{21}{5}

Solution steps

5 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 5 : 221 i

x_{1, 2} = \frac{- 4 \pm 2 21 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 2 21 i}{2 \cdot 5}, x_{2} = \frac{- 4 - 2 21 i}{2 \cdot 5}

x = \frac{- 4 + 2 21 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{21}{5}

x = \frac{- 4 - 2 21 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{21}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} + i \frac{21}{5}, x = - \frac{2}{5} - i \frac{21}{5}

x, x^{2} + 10 x + 25 = 0

x, (x + 2)^{2} - (y + 5)^{2} = 0

x^{2} + 6 x - 216 = 0

9 x^{2} - 12 + 4 = 0

(x) = x^{2} + 6 x + 8

What are the solutions to the equation 5x^2+4x+5=0 ?
The solutions to the equation 5x^2+4x+5=0 are x=-2/5+i(sqrt(21))/5 ,x=-2/5-i(sqrt(21))/5
Find the zeros of 5x^2+4x+5=0
The zeros of 5x^2+4x+5=0 are x=-2/5+i(sqrt(21))/5 ,x=-2/5-i(sqrt(21))/5