What are the solutions to the equation x^2+32x+16=0 ?

The solutions to the equation x^2+32x+16=0 are x=4(sqrt(15)-4),x=-4(4+sqrt(15))

Find the zeros of x^2+32x+16=0

The zeros of x^2+32x+16=0 are x=4(sqrt(15)-4),x=-4(4+sqrt(15))

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x^{2} + 32 x + 16 = 0

x = 4 (15 - 4), x = - 4 (4 + 15)

Decimal Notation

x = - 0.50806 \dots, x = - 31.49193 \dots

Solution steps

x^{2} + 32 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

3 2^{2} - 4 \cdot 1 \cdot 16 = 815

x_{1, 2} = \frac{- 32 \pm 8 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 32 + 8 15}{2 \cdot 1}, x_{2} = \frac{- 32 - 8 15}{2 \cdot 1}

x = \frac{- 32 + 8 15}{2 \cdot 1} : 4 (15 - 4)

x = \frac{- 32 - 8 15}{2 \cdot 1} : - 4 (4 + 15)

The solutions to the quadratic equation are:

x = 4 (15 - 4), x = - 4 (4 + 15)

y^{2} - 20 y + 100 = 0

x^{2} + 5 (m - 1) x + m^{2} = 0

- 6 x^{2} - 5 x + 4 = 0

x^{2} + 0.9 x - 7.92 = 0

y^{2} + 4 y - 6 = 0

What are the solutions to the equation x^2+32x+16=0 ?
The solutions to the equation x^2+32x+16=0 are x=4(sqrt(15)-4),x=-4(4+sqrt(15))
Find the zeros of x^2+32x+16=0
The zeros of x^2+32x+16=0 are x=4(sqrt(15)-4),x=-4(4+sqrt(15))