What are the solutions to the equation x^2+x=-3/4 ?

The solutions to the equation x^2+x=-3/4 are x=-1/2+i(sqrt(2))/2 ,x=-1/2-i(sqrt(2))/2

Find the zeros of x^2+x=-3/4

The zeros of x^2+x=-3/4 are x=-1/2+i(sqrt(2))/2 ,x=-1/2-i(sqrt(2))/2

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x^{2} + x = - \frac{3}{4}

x = - \frac{1}{2} + i \frac{2}{2}, x = - \frac{1}{2} - i \frac{2}{2}

Solution steps

x^{2} + x = - \frac{3}{4}

Multiply both sides by

4

4 x^{2} + 4 x = - 3

Move

3

to the left side

4 x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 3 : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 2 i}{2 \cdot 4}

x = \frac{- 4 + 4 2 i}{2 \cdot 4} : - \frac{1}{2} + i \frac{2}{2}

x = \frac{- 4 - 4 2 i}{2 \cdot 4} : - \frac{1}{2} - i \frac{2}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{2}{2}, x = - \frac{1}{2} - i \frac{2}{2}

x^{2} + 16 x - 9 = 0

x^{2} + 8 x + c

- 5 x - 13 + 7 x^{2} = 3 x^{2}

2 x^{2} + x - 20 = 0

t, s = \frac{1}{2} g t^{2} + v t

What are the solutions to the equation x^2+x=-3/4 ?
The solutions to the equation x^2+x=-3/4 are x=-1/2+i(sqrt(2))/2 ,x=-1/2-i(sqrt(2))/2
Find the zeros of x^2+x=-3/4
The zeros of x^2+x=-3/4 are x=-1/2+i(sqrt(2))/2 ,x=-1/2-i(sqrt(2))/2