What are the solutions to the equation -2x^2+11x-15=0 ?

The solutions to the equation -2x^2+11x-15=0 are x= 5/2 ,x=3

Find the zeros of -2x^2+11x-15=0

The zeros of -2x^2+11x-15=0 are x= 5/2 ,x=3

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- 2 x^{2} + 11 x - 15 = 0

x = \frac{5}{2}, x = 3

Decimal Notation

x = 2.5, x = 3

Solution steps

- 2 x^{2} + 11 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 2 ) ( - 15 )}{2 ( - 2 )}

1 1^{2} - 4 (- 2) (- 15) = 1

x_{1, 2} = \frac{- 11 \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 11 + 1}{2 ( - 2 )}, x_{2} = \frac{- 11 - 1}{2 ( - 2 )}

x = \frac{- 11 + 1}{2 ( - 2 )} : \frac{5}{2}

x = \frac{- 11 - 1}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 3

x = - x^{2} - 48 x + 64

2 + \frac{2}{20} Q - \frac{3}{20} Q^{2} = 0

7 = x^{2} + 4 x + 4

(x^{2} - 6 x + 9) = 0

128 - 6 x^{2} = 0

What are the solutions to the equation -2x^2+11x-15=0 ?
The solutions to the equation -2x^2+11x-15=0 are x= 5/2 ,x=3
Find the zeros of -2x^2+11x-15=0
The zeros of -2x^2+11x-15=0 are x= 5/2 ,x=3