What are the solutions to the equation (x^2-6x+9)=0 ?

The solutions to the equation (x^2-6x+9)=0 are x=3

Find the zeros of (x^2-6x+9)=0

The zeros of (x^2-6x+9)=0 are x=3

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(x^{2} - 6 x + 9) = 0

x = 3

Solution steps

(x^{2} - 6 x + 9) = 0

Refine

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

128 - 6 x^{2} = 0

x^{2} = 1 0^{2} + 2 4^{2}

(x + 1) (x + 6) = - 6

(x - 2)^{2} - 10 (x - 2) + 9 = 0

1650 + 45 x + x^{2} = 130 x

What are the solutions to the equation (x^2-6x+9)=0 ?
The solutions to the equation (x^2-6x+9)=0 are x=3
Find the zeros of (x^2-6x+9)=0
The zeros of (x^2-6x+9)=0 are x=3