What are the solutions to the equation 4x^2+8x+80=0 ?

The solutions to the equation 4x^2+8x+80=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i

Find the zeros of 4x^2+8x+80=0

The zeros of 4x^2+8x+80=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i

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4 x^{2} + 8 x + 80 = 0

x = - 1 + 19 i, x = - 1 - 19 i

Solution steps

4 x^{2} + 8 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 80}{2 \cdot 4}

Simplify

8^{2} - 4 \cdot 4 \cdot 80 : 819 i

x_{1, 2} = \frac{- 8 \pm 8 19 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 8 19 i}{2 \cdot 4}, x_{2} = \frac{- 8 - 8 19 i}{2 \cdot 4}

x = \frac{- 8 + 8 19 i}{2 \cdot 4} : - 1 + 19 i

x = \frac{- 8 - 8 19 i}{2 \cdot 4} : - 1 - 19 i

The solutions to the quadratic equation are:

x = - 1 + 19 i, x = - 1 - 19 i

(2 D - 1)^{2} = 0

14 = x^{2} + 5 x

(x + 9)^{2} = x^{2} + (x + 1)^{2}

4 x^{2} - 3 = x

(m - 2)^{2} = (m - 4)^{2} + (m - 3)^{2}

What are the solutions to the equation 4x^2+8x+80=0 ?
The solutions to the equation 4x^2+8x+80=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i
Find the zeros of 4x^2+8x+80=0
The zeros of 4x^2+8x+80=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i