What are the solutions to the equation x^2+6x-189=0 ?

The solutions to the equation x^2+6x-189=0 are x=3(sqrt(22)-1),x=-3(1+sqrt(22))

Find the zeros of x^2+6x-189=0

The zeros of x^2+6x-189=0 are x=3(sqrt(22)-1),x=-3(1+sqrt(22))

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x^{2} + 6 x - 189 = 0

x = 3 (22 - 1), x = - 3 (1 + 22)

Decimal Notation

x = 11.07124 \dots, x = - 17.07124 \dots

Solution steps

x^{2} + 6 x - 189 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 189 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 189) = 622

x_{1, 2} = \frac{- 6 \pm 6 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 6 22}{2 \cdot 1}, x_{2} = \frac{- 6 - 6 22}{2 \cdot 1}

x = \frac{- 6 + 6 22}{2 \cdot 1} : 3 (22 - 1)

x = \frac{- 6 - 6 22}{2 \cdot 1} : - 3 (1 + 22)

The solutions to the quadratic equation are:

x = 3 (22 - 1), x = - 3 (1 + 22)

- 8 x^{2} + x - 2 = - 18

x^{2} + \frac{29}{4} x + \frac{7}{4} = 0

y^{2} - 2 = 6 - y^{2}

x^{2} - 12 x + 36 = 0

25 - x^{3} = (4 - x)^{3}

What are the solutions to the equation x^2+6x-189=0 ?
The solutions to the equation x^2+6x-189=0 are x=3(sqrt(22)-1),x=-3(1+sqrt(22))
Find the zeros of x^2+6x-189=0
The zeros of x^2+6x-189=0 are x=3(sqrt(22)-1),x=-3(1+sqrt(22))