What are the solutions to the equation -2(x-9)^2+200=0 ?

The solutions to the equation -2(x-9)^2+200=0 are x=19,x=-1

Find the zeros of -2(x-9)^2+200=0

The zeros of -2(x-9)^2+200=0 are x=19,x=-1

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- 2 (x - 9)^{2} + 200 = 0

x = 19, x = - 1

Solution steps

- 2 (x - 9)^{2} + 200 = 0

Move

200

to the right side

- 2 (x - 9)^{2} = - 200

Divide both sides by

- 2

(x - 9)^{2} = 100

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = 100 : x = 19

Solve

x - 9 = - 100 : x = - 1

The solutions to the quadratic equation are:

x = 19, x = - 1

x, 3 x^{2} - 2 y^{2} - 18 x + 16 y - 5 = 0

x^{2} + 24 x + 100 = - 46

x^{2} - 3 = 61

\frac{1}{3} r^{2} + 3 r + 6 = 0

6 x^{2} = 2 x + 1

What are the solutions to the equation -2(x-9)^2+200=0 ?
The solutions to the equation -2(x-9)^2+200=0 are x=19,x=-1
Find the zeros of -2(x-9)^2+200=0
The zeros of -2(x-9)^2+200=0 are x=19,x=-1