What are the solutions to the equation x^2+24x+100=-46 ?

The solutions to the equation x^2+24x+100=-46 are x=-12+sqrt(2)i,x=-12-sqrt(2)i

Find the zeros of x^2+24x+100=-46

The zeros of x^2+24x+100=-46 are x=-12+sqrt(2)i,x=-12-sqrt(2)i

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x^{2} + 24 x + 100 = - 46

x = - 12 + 2 i, x = - 12 - 2 i

Solution steps

x^{2} + 24 x + 100 = - 46

Move

46

to the left side

x^{2} + 24 x + 146 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 146}{2 \cdot 1}

Simplify

2 4^{2} - 4 \cdot 1 \cdot 146 : 22 i

x_{1, 2} = \frac{- 24 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 24 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 24 - 2 2 i}{2 \cdot 1}

x = \frac{- 24 + 2 2 i}{2 \cdot 1} : - 12 + 2 i

x = \frac{- 24 - 2 2 i}{2 \cdot 1} : - 12 - 2 i

The solutions to the quadratic equation are:

x = - 12 + 2 i, x = - 12 - 2 i

x^{2} - 3 = 61

\frac{1}{3} r^{2} + 3 r + 6 = 0

6 x^{2} = 2 x + 1

- 13 = x^{2} - 4 x

160 - 104 x + 12 x^{2} = 0

What are the solutions to the equation x^2+24x+100=-46 ?
The solutions to the equation x^2+24x+100=-46 are x=-12+sqrt(2)i,x=-12-sqrt(2)i
Find the zeros of x^2+24x+100=-46
The zeros of x^2+24x+100=-46 are x=-12+sqrt(2)i,x=-12-sqrt(2)i