What are the solutions to the equation (2x-4)^2=64 ?

The solutions to the equation (2x-4)^2=64 are x=6,x=-2

Find the zeros of (2x-4)^2=64

The zeros of (2x-4)^2=64 are x=6,x=-2

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(2 x - 4)^{2} = 64

x = 6, x = - 2

Solution steps

(2 x - 4)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 64 : x = 6

Solve

2 x - 4 = - 64 : x = - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

x^{2} + 10 x + 20 = - 5

4 x - 7 x = 1 - 7 x^{2} + 5 - 3 x^{2} + 7 x + 8 x^{2} - 6

k, y^{n} + k^{2} y = 0

m^{2} + 8 m = 16

(x - 2)^{2} - 2 (x - 2) - 15 = 0

What are the solutions to the equation (2x-4)^2=64 ?
The solutions to the equation (2x-4)^2=64 are x=6,x=-2
Find the zeros of (2x-4)^2=64
The zeros of (2x-4)^2=64 are x=6,x=-2