What are the solutions to the equation s^2-0.5s+0.5=0 ?

The solutions to the equation s^2-0.5s+0.5=0 are s= 1/4+i(sqrt(7))/4 ,s= 1/4-i(sqrt(7))/4

Find the zeros of s^2-0.5s+0.5=0

The zeros of s^2-0.5s+0.5=0 are s= 1/4+i(sqrt(7))/4 ,s= 1/4-i(sqrt(7))/4

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s^{2} - 0.5 s + 0.5 = 0

s = \frac{1}{4} + i \frac{7}{4}, s = \frac{1}{4} - i \frac{7}{4}

Solution steps

s^{2} - 0.5 s + 0.5 = 0

Multiply both sides by

10

10 s^{2} - 5 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 10 \cdot 5}{2 \cdot 10}

Simplify

(- 5)^{2} - 4 \cdot 10 \cdot 5 : 57 i

s_{1, 2} = \frac{- ( - 5 ) \pm 5 7 i}{2 \cdot 10}

Separate the solutions

s_{1} = \frac{- ( - 5 ) + 5 7 i}{2 \cdot 10}, s_{2} = \frac{- ( - 5 ) - 5 7 i}{2 \cdot 10}

s = \frac{- ( - 5 ) + 5 7 i}{2 \cdot 10} : \frac{1}{4} + i \frac{7}{4}

s = \frac{- ( - 5 ) - 5 7 i}{2 \cdot 10} : \frac{1}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

s = \frac{1}{4} + i \frac{7}{4}, s = \frac{1}{4} - i \frac{7}{4}

4 k (k + 3) = - 11

3 x^{2} - 3 x = 9

2 p^{2} + 8 p + (k + 1) = 0

x^{2} + 2 x - 3 = 0

s^{2} + 2 s + 2 = 0

What are the solutions to the equation s^2-0.5s+0.5=0 ?
The solutions to the equation s^2-0.5s+0.5=0 are s= 1/4+i(sqrt(7))/4 ,s= 1/4-i(sqrt(7))/4
Find the zeros of s^2-0.5s+0.5=0
The zeros of s^2-0.5s+0.5=0 are s= 1/4+i(sqrt(7))/4 ,s= 1/4-i(sqrt(7))/4