What are the solutions to the equation -x^2+2x+3=x+1 ?

The solutions to the equation -x^2+2x+3=x+1 are x=-1,x=2

Find the zeros of -x^2+2x+3=x+1

The zeros of -x^2+2x+3=x+1 are x=-1,x=2

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- x^{2} + 2 x + 3 = x + 1

x = - 1, x = 2

Solution steps

- x^{2} + 2 x + 3 = x + 1

Move

1

to the left side

- x^{2} + 2 x + 2 = x

Move

x

to the left side

- x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 2 = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 ( - 1 )}, x_{2} = \frac{- 1 - 3}{2 ( - 1 )}

x = \frac{- 1 + 3}{2 ( - 1 )} : - 1

x = \frac{- 1 - 3}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

t, d = \frac{1}{2} a t^{2}

\frac{3}{25} x^{2} - \frac{7}{30} x + \frac{12}{150} = 0

(x - 2)^{2} + 3 = 19

a^{2} + 7 a - 60 = 0

9 - 2 x (x + 4) - 10 (25 - x + 4) = 5 - 3 x - 4 (x + 1)

What are the solutions to the equation -x^2+2x+3=x+1 ?
The solutions to the equation -x^2+2x+3=x+1 are x=-1,x=2
Find the zeros of -x^2+2x+3=x+1
The zeros of -x^2+2x+3=x+1 are x=-1,x=2