What are the solutions to the equation a^2+7a-60=0 ?

The solutions to the equation a^2+7a-60=0 are a=5,a=-12

Find the zeros of a^2+7a-60=0

The zeros of a^2+7a-60=0 are a=5,a=-12

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a^{2} + 7 a - 60 = 0

a = 5, a = - 12

Solution steps

a^{2} + 7 a - 60 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 60) = 17

a_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 7 + 17}{2 \cdot 1}, a_{2} = \frac{- 7 - 17}{2 \cdot 1}

a = \frac{- 7 + 17}{2 \cdot 1} : 5

a = \frac{- 7 - 17}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

a = 5, a = - 12

9 - 2 x (x + 4) - 10 (25 - x + 4) = 5 - 3 x - 4 (x + 1)

49 x^{2} - 49 = 0

9 x^{2} - 12 x + 4 = 0

x^{2} + 6 x = 7

x^{2} - 13 x - 72 = - 7 x

What are the solutions to the equation a^2+7a-60=0 ?
The solutions to the equation a^2+7a-60=0 are a=5,a=-12
Find the zeros of a^2+7a-60=0
The zeros of a^2+7a-60=0 are a=5,a=-12