What are the solutions to the equation (x-2)^2+3=19 ?

The solutions to the equation (x-2)^2+3=19 are x=6,x=-2

Find the zeros of (x-2)^2+3=19

The zeros of (x-2)^2+3=19 are x=6,x=-2

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(x - 2)^{2} + 3 = 19

x = 6, x = - 2

Solution steps

(x - 2)^{2} + 3 = 19

Move

3

to the right side

(x - 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 16 : x = 6

Solve

x - 2 = - 16 : x = - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

a^{2} + 7 a - 60 = 0

9 - 2 x (x + 4) - 10 (25 - x + 4) = 5 - 3 x - 4 (x + 1)

49 x^{2} - 49 = 0

9 x^{2} - 12 x + 4 = 0

x^{2} + 6 x = 7

What are the solutions to the equation (x-2)^2+3=19 ?
The solutions to the equation (x-2)^2+3=19 are x=6,x=-2
Find the zeros of (x-2)^2+3=19
The zeros of (x-2)^2+3=19 are x=6,x=-2