What are the solutions to the equation x^2+10x+25=12 ?

The solutions to the equation x^2+10x+25=12 are x=-5+2sqrt(3),x=-5-2sqrt(3)

Find the zeros of x^2+10x+25=12

The zeros of x^2+10x+25=12 are x=-5+2sqrt(3),x=-5-2sqrt(3)

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x^{2} + 10 x + 25 = 12

x = - 5 + 23, x = - 5 - 23

Decimal Notation

x = - 1.53589 \dots, x = - 8.46410 \dots

Solution steps

x^{2} + 10 x + 25 = 12

Move

12

to the left side

x^{2} + 10 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 13 = 43

x_{1, 2} = \frac{- 10 \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 4 3}{2 \cdot 1}, x_{2} = \frac{- 10 - 4 3}{2 \cdot 1}

x = \frac{- 10 + 4 3}{2 \cdot 1} : - 5 + 23

x = \frac{- 10 - 4 3}{2 \cdot 1} : - 5 - 23

The solutions to the quadratic equation are:

x = - 5 + 23, x = - 5 - 23

x^{2} = 1 0^{2} + 8^{2}

x^{2} - 12 x - 91 = - 6

(x - 2)^{2} + 3 (3 x - 4) (3 x + 4) = 7 (4 x - 3) - 23

2 x^{2} - 13 x + 2 = 0

x^{2} - 10 x = 0

What are the solutions to the equation x^2+10x+25=12 ?
The solutions to the equation x^2+10x+25=12 are x=-5+2sqrt(3),x=-5-2sqrt(3)
Find the zeros of x^2+10x+25=12
The zeros of x^2+10x+25=12 are x=-5+2sqrt(3),x=-5-2sqrt(3)