What are the solutions to the equation 9x^2+10=91 ?

The solutions to the equation 9x^2+10=91 are x=3,x=-3

Find the zeros of 9x^2+10=91

The zeros of 9x^2+10=91 are x=3,x=-3

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9 x^{2} + 10 = 91

x = 3, x = - 3

Solution steps

9 x^{2} + 10 = 91

Move

10

to the right side

9 x^{2} = 81

Divide both sides by

9

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

b, A = \frac{1}{2} (b^{1} + b^{2}) h

2 (x - 4) (x - 4) - 18 = 0

X^{2} + 4 X - 6 = 0

y, x = 2 (y - 1)^{2} + 2

x - 1 = x^{2}

What are the solutions to the equation 9x^2+10=91 ?
The solutions to the equation 9x^2+10=91 are x=3,x=-3
Find the zeros of 9x^2+10=91
The zeros of 9x^2+10=91 are x=3,x=-3