What are the solutions to the equation quadraticformula 4a^2+6=0 ?

The solutions to the equation quadraticformula 4a^2+6=0 are a=isqrt(3/2),a=-isqrt(3/2)

Find the zeros of quadraticformula 4a^2+6=0

The zeros of quadraticformula 4a^2+6=0 are a=isqrt(3/2),a=-isqrt(3/2)

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4 a^{2} + 6 = 0

a = i \frac{3}{2}, a = - i \frac{3}{2}

Solution steps

4 a^{2} + 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

Simplify

0^{2} - 4 \cdot 4 \cdot 6 : 46 i

a_{1, 2} = \frac{- 0 \pm 4 6 i}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- 0 + 4 6 i}{2 \cdot 4}, a_{2} = \frac{- 0 - 4 6 i}{2 \cdot 4}

a = \frac{- 0 + 4 6 i}{2 \cdot 4} : i \frac{3}{2}

a = \frac{- 0 - 4 6 i}{2 \cdot 4} : - i \frac{3}{2}

The solutions to the quadratic equation are:

a = i \frac{3}{2}, a = - i \frac{3}{2}

x^{2} + 5 = 2

w^{2} - w - 2 = 0

x^{2} + 2 = 7

\frac{x + 1}{4} - \frac{x ^{2} - 2}{3} = \frac{x ^{2} - 2}{6} + 1

x^{2} - 14 x + 44 = 0

What are the solutions to the equation quadraticformula 4a^2+6=0 ?
The solutions to the equation quadraticformula 4a^2+6=0 are a=isqrt(3/2),a=-isqrt(3/2)
Find the zeros of quadraticformula 4a^2+6=0
The zeros of quadraticformula 4a^2+6=0 are a=isqrt(3/2),a=-isqrt(3/2)