What are the solutions to the equation s^2+9s+9=0 ?

The solutions to the equation s^2+9s+9=0 are s=(-9+3sqrt(5))/2 ,s=(-9-3sqrt(5))/2

Find the zeros of s^2+9s+9=0

The zeros of s^2+9s+9=0 are s=(-9+3sqrt(5))/2 ,s=(-9-3sqrt(5))/2

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s^{2} + 9 s + 9 = 0

s = \frac{- 9 + 3 5}{2}, s = \frac{- 9 - 3 5}{2}

Decimal Notation

s = - 1.14589 \dots, s = - 7.85410 \dots

Solution steps

s^{2} + 9 s + 9 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 9 = 35

s_{1, 2} = \frac{- 9 \pm 3 5}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 9 + 3 5}{2 \cdot 1}, s_{2} = \frac{- 9 - 3 5}{2 \cdot 1}

s = \frac{- 9 + 3 5}{2 \cdot 1} : \frac{- 9 + 3 5}{2}

s = \frac{- 9 - 3 5}{2 \cdot 1} : \frac{- 9 - 3 5}{2}

The solutions to the quadratic equation are:

s = \frac{- 9 + 3 5}{2}, s = \frac{- 9 - 3 5}{2}

x^{2} + 2 x + 4 = 0

x, 9 x^{2} = 4 y^{3}

x^{2} + 17 x + 12 = - 3 x^{2}

(x - 4) (x + 4) = 9

(x - 4) (x + 4) = 0

What are the solutions to the equation s^2+9s+9=0 ?
The solutions to the equation s^2+9s+9=0 are s=(-9+3sqrt(5))/2 ,s=(-9-3sqrt(5))/2
Find the zeros of s^2+9s+9=0
The zeros of s^2+9s+9=0 are s=(-9+3sqrt(5))/2 ,s=(-9-3sqrt(5))/2