What are the solutions to the equation -14x+168-7x^2=0 ?

The solutions to the equation -14x+168-7x^2=0 are x=-6,x=4

Find the zeros of -14x+168-7x^2=0

The zeros of -14x+168-7x^2=0 are x=-6,x=4

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- 14 x + 168 - 7 x^{2} = 0

x = - 6, x = 4

Solution steps

- 14 x + 168 - 7 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 x^{2} - 14 x + 168 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 7 ) \cdot 168}{2 ( - 7 )}

(- 14)^{2} - 4 (- 7) \cdot 168 = 70

x_{1, 2} = \frac{- ( - 14 ) \pm 70}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 70}{2 ( - 7 )}, x_{2} = \frac{- ( - 14 ) - 70}{2 ( - 7 )}

x = \frac{- ( - 14 ) + 70}{2 ( - 7 )} : - 6

x = \frac{- ( - 14 ) - 70}{2 ( - 7 )} : 4

The solutions to the quadratic equation are:

x = - 6, x = 4

x^{2} - 25 = (a + b) (a - c)

- 2 x^{2} + 12 x - 20 = 0

2 x^{2} - 15 = 65

(2 x + 1) \cdot (x + 3) - x \cdot (x - 2) = 0

x^{2} + 10 x + 12 = 2 x + 52 x + 5

What are the solutions to the equation -14x+168-7x^2=0 ?
The solutions to the equation -14x+168-7x^2=0 are x=-6,x=4
Find the zeros of -14x+168-7x^2=0
The zeros of -14x+168-7x^2=0 are x=-6,x=4