What are the solutions to the equation 18x^2-288x+864=0 ?

The solutions to the equation 18x^2-288x+864=0 are x=12,x=4

Find the zeros of 18x^2-288x+864=0

The zeros of 18x^2-288x+864=0 are x=12,x=4

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18 x^{2} - 288 x + 864 = 0

x = 12, x = 4

Solution steps

18 x^{2} - 288 x + 864 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 288 ) \pm ( - 288 ) ^{2} - 4 \cdot 18 \cdot 864}{2 \cdot 18}

(- 288)^{2} - 4 \cdot 18 \cdot 864 = 144

x_{1, 2} = \frac{- ( - 288 ) \pm 144}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 288 ) + 144}{2 \cdot 18}, x_{2} = \frac{- ( - 288 ) - 144}{2 \cdot 18}

x = \frac{- ( - 288 ) + 144}{2 \cdot 18} : 12

x = \frac{- ( - 288 ) - 144}{2 \cdot 18} : 4

The solutions to the quadratic equation are:

x = 12, x = 4

32 - 2 x^{2} = 0

0 = 5 x^{2} + 35 x - 90

x^{2} - 4 x + 1 = 0

w^{2} + 6 w - 11 = 0

x^{2} - 4 x + 3 = 0

What are the solutions to the equation 18x^2-288x+864=0 ?
The solutions to the equation 18x^2-288x+864=0 are x=12,x=4
Find the zeros of 18x^2-288x+864=0
The zeros of 18x^2-288x+864=0 are x=12,x=4