What are the solutions to the equation 5x^2-10x=-5 ?

The solutions to the equation 5x^2-10x=-5 are x=1

Find the zeros of 5x^2-10x=-5

The zeros of 5x^2-10x=-5 are x=1

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5 x^{2} - 10 x = - 5

x = 1

Solution steps

5 x^{2} - 10 x = - 5

Move

5

to the left side

5 x^{2} - 10 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 \cdot 5 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 5}

x = \frac{- ( - 10 )}{2 \cdot 5}

\frac{- ( - 10 )}{2 \cdot 5} = 1

x = 1

The solution to the quadratic equation is:

x = 1

4 + 49 y^{2} = 0

x (x + 6) = 91

D, (2 D - 1)^{2} y = 0

4 x^{2} - 4 x - 5 = 0

x^{2} - 1 = - 7 x

What are the solutions to the equation 5x^2-10x=-5 ?
The solutions to the equation 5x^2-10x=-5 are x=1
Find the zeros of 5x^2-10x=-5
The zeros of 5x^2-10x=-5 are x=1