What are the solutions to the equation 4+49y^2=0 ?

The solutions to the equation 4+49y^2=0 are y= 2/7 i,y=-2/7 i

Find the zeros of 4+49y^2=0

The zeros of 4+49y^2=0 are y= 2/7 i,y=-2/7 i

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4 + 49 y^{2} = 0

y = \frac{2}{7} i, y = - \frac{2}{7} i

Solution steps

4 + 49 y^{2} = 0

Move

4

to the right side

49 y^{2} = - 4

Divide both sides by

49

y^{2} = - \frac{4}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{4}{49}, y = - - \frac{4}{49}

- \frac{4}{49} = \frac{2}{7} i

- - \frac{4}{49} = - \frac{2}{7} i

y = \frac{2}{7} i, y = - \frac{2}{7} i

x (x + 6) = 91

D, (2 D - 1)^{2} y = 0

4 x^{2} - 4 x - 5 = 0

x^{2} - 1 = - 7 x

x^{2} - 4 x + 4 = 2 x

What are the solutions to the equation 4+49y^2=0 ?
The solutions to the equation 4+49y^2=0 are y= 2/7 i,y=-2/7 i
Find the zeros of 4+49y^2=0
The zeros of 4+49y^2=0 are y= 2/7 i,y=-2/7 i