What are the solutions to the equation 3x^2+18x+6=0 ?

The solutions to the equation 3x^2+18x+6=0 are x=-3+sqrt(7),x=-3-sqrt(7)

Find the zeros of 3x^2+18x+6=0

The zeros of 3x^2+18x+6=0 are x=-3+sqrt(7),x=-3-sqrt(7)

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3 x^{2} + 18 x + 6 = 0

x = - 3 + 7, x = - 3 - 7

Decimal Notation

x = - 0.35424 \dots, x = - 5.64575 \dots

Solution steps

3 x^{2} + 18 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 6 = 67

x_{1, 2} = \frac{- 18 \pm 6 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 6 7}{2 \cdot 3}, x_{2} = \frac{- 18 - 6 7}{2 \cdot 3}

x = \frac{- 18 + 6 7}{2 \cdot 3} : - 3 + 7

x = \frac{- 18 - 6 7}{2 \cdot 3} : - 3 - 7

The solutions to the quadratic equation are:

x = - 3 + 7, x = - 3 - 7

4 x^{2} + 44 x + 112 = 0

- 2 x^{2} + x + 7 = 0

x^{2} + 3 x - 2 = 0, 5 x^{2} - 8 (x - 2) + 7 (x + 1) = x^{2} - 2

x, 8 x^{2} + 12 x y - 80 y^{2} = 0

v^{2} - 13 v + 8 = - 4

What are the solutions to the equation 3x^2+18x+6=0 ?
The solutions to the equation 3x^2+18x+6=0 are x=-3+sqrt(7),x=-3-sqrt(7)
Find the zeros of 3x^2+18x+6=0
The zeros of 3x^2+18x+6=0 are x=-3+sqrt(7),x=-3-sqrt(7)