What are the solutions to the equation 0=-t^2+3t+27 ?

The solutions to the equation 0=-t^2+3t+27 are t=-(-3+3sqrt(13))/2 ,t=(3+3sqrt(13))/2

Find the zeros of 0=-t^2+3t+27

The zeros of 0=-t^2+3t+27 are t=-(-3+3sqrt(13))/2 ,t=(3+3sqrt(13))/2

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0 = - t^{2} + 3 t + 27

t = - \frac{- 3 + 3 13}{2}, t = \frac{3 + 3 13}{2}

Decimal Notation

t = - 3.90832 \dots, t = 6.90832 \dots

Solution steps

0 = - t^{2} + 3 t + 27

Switch sides

- t^{2} + 3 t + 27 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 27}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 27 = 313

t_{1, 2} = \frac{- 3 \pm 3 13}{2 ( - 1 )}

Separate the solutions

t_{1} = \frac{- 3 + 3 13}{2 ( - 1 )}, t_{2} = \frac{- 3 - 3 13}{2 ( - 1 )}

t = \frac{- 3 + 3 13}{2 ( - 1 )} : - \frac{- 3 + 3 13}{2}

t = \frac{- 3 - 3 13}{2 ( - 1 )} : \frac{3 + 3 13}{2}

The solutions to the quadratic equation are:

t = - \frac{- 3 + 3 13}{2}, t = \frac{3 + 3 13}{2}

x^{2} + 28 x = 23.04

x^{2} + x - 21 = 0

(2 x + 5) (3 x - 2) = 4

- x^{2} - 7 x = 6

\frac{x}{5000} = \frac{4}{2000} (5 - x - 0.3)^{2}

What are the solutions to the equation 0=-t^2+3t+27 ?
The solutions to the equation 0=-t^2+3t+27 are t=-(-3+3sqrt(13))/2 ,t=(3+3sqrt(13))/2
Find the zeros of 0=-t^2+3t+27
The zeros of 0=-t^2+3t+27 are t=-(-3+3sqrt(13))/2 ,t=(3+3sqrt(13))/2