What are the solutions to the equation x^2+28x=23.04 ?

The solutions to the equation x^2+28x=23.04 are x= 4/5 ,x=-144/5

Find the zeros of x^2+28x=23.04

The zeros of x^2+28x=23.04 are x= 4/5 ,x=-144/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 28 x = 23.04

x = \frac{4}{5}, x = - \frac{144}{5}

Decimal Notation

x = 0.8, x = - 28.8

Solution steps

x^{2} + 28 x = 23.04

Multiply both sides by

100

100 x^{2} + 2800 x = 2304

Move

2304

to the left side

100 x^{2} + 2800 x - 2304 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2800 \pm 280 0 ^{2} - 4 \cdot 100 ( - 2304 )}{2 \cdot 100}

280 0^{2} - 4 \cdot 100 (- 2304) = 2960

x_{1, 2} = \frac{- 2800 \pm 2960}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 2800 + 2960}{2 \cdot 100}, x_{2} = \frac{- 2800 - 2960}{2 \cdot 100}

x = \frac{- 2800 + 2960}{2 \cdot 100} : \frac{4}{5}

x = \frac{- 2800 - 2960}{2 \cdot 100} : - \frac{144}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = - \frac{144}{5}

x^{2} + x - 21 = 0

(2 x + 5) (3 x - 2) = 4

- x^{2} - 7 x = 6

\frac{x}{5000} = \frac{4}{2000} (5 - x - 0.3)^{2}

2 (x - 1)^{2} + 3 = 6

What are the solutions to the equation x^2+28x=23.04 ?
The solutions to the equation x^2+28x=23.04 are x= 4/5 ,x=-144/5
Find the zeros of x^2+28x=23.04
The zeros of x^2+28x=23.04 are x= 4/5 ,x=-144/5