What are the solutions to the equation x^2-3x+7=x+52 ?

The solutions to the equation x^2-3x+7=x+52 are x=9,x=-5

Find the zeros of x^2-3x+7=x+52

The zeros of x^2-3x+7=x+52 are x=9,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x + 7 = x + 52

x = 9, x = - 5

Solution steps

x^{2} - 3 x + 7 = x + 52

Move

52

to the left side

x^{2} - 3 x - 45 = x

Move

x

to the left side

x^{2} - 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 1}

x = \frac{- ( - 4 ) + 14}{2 \cdot 1} : 9

x = \frac{- ( - 4 ) - 14}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 9, x = - 5

5 - 4 x - x^{2}

4 x (x - 3) - (x - 1) (x + 3) = 2 (x - 3)^{2}

s^{2} + 3 s + 3 = 0

4 x^{2} + 31 x + 21 = 0

2 r^{2} + 8 r + 8 = 0

What are the solutions to the equation x^2-3x+7=x+52 ?
The solutions to the equation x^2-3x+7=x+52 are x=9,x=-5
Find the zeros of x^2-3x+7=x+52
The zeros of x^2-3x+7=x+52 are x=9,x=-5