What are the solutions to the equation s^2+3s+3=0 ?

The solutions to the equation s^2+3s+3=0 are s=-3/2+i(sqrt(3))/2 ,s=-3/2-i(sqrt(3))/2

Find the zeros of s^2+3s+3=0

The zeros of s^2+3s+3=0 are s=-3/2+i(sqrt(3))/2 ,s=-3/2-i(sqrt(3))/2

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s^{2} + 3 s + 3 = 0

s = - \frac{3}{2} + i \frac{3}{2}, s = - \frac{3}{2} - i \frac{3}{2}

Solution steps

s^{2} + 3 s + 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 3 : 3 i

s_{1, 2} = \frac{- 3 \pm 3 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 3 + 3 i}{2 \cdot 1}, s_{2} = \frac{- 3 - 3 i}{2 \cdot 1}

s = \frac{- 3 + 3 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{3}{2}

s = \frac{- 3 - 3 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

s = - \frac{3}{2} + i \frac{3}{2}, s = - \frac{3}{2} - i \frac{3}{2}

4 x^{2} + 31 x + 21 = 0

2 r^{2} + 8 r + 8 = 0

2 x^{2} - 6 x + 6 = c^{1} (x^{2} + x - 1) + c^{2} (x^{2} - x + 1)

(2 x - 10) (3 x + 12) = 0

a^{2} - 2 a = 2

What are the solutions to the equation s^2+3s+3=0 ?
The solutions to the equation s^2+3s+3=0 are s=-3/2+i(sqrt(3))/2 ,s=-3/2-i(sqrt(3))/2
Find the zeros of s^2+3s+3=0
The zeros of s^2+3s+3=0 are s=-3/2+i(sqrt(3))/2 ,s=-3/2-i(sqrt(3))/2