What are the solutions to the equation (10-2x)(14-2x)=32 ?

The solutions to the equation (10-2x)(14-2x)=32 are x=9,x=3

Find the zeros of (10-2x)(14-2x)=32

The zeros of (10-2x)(14-2x)=32 are x=9,x=3

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(10 - 2 x) (14 - 2 x) = 32

x = 9, x = 3

Solution steps

(10 - 2 x) (14 - 2 x) = 32

Expand

(10 - 2 x) (14 - 2 x) : 140 - 48 x + 4 x^{2}

140 - 48 x + 4 x^{2} = 32

Move

32

to the left side

4 x^{2} - 48 x + 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 4 \cdot 108}{2 \cdot 4}

(- 48)^{2} - 4 \cdot 4 \cdot 108 = 24

x_{1, 2} = \frac{- ( - 48 ) \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 24}{2 \cdot 4}, x_{2} = \frac{- ( - 48 ) - 24}{2 \cdot 4}

x = \frac{- ( - 48 ) + 24}{2 \cdot 4} : 9

x = \frac{- ( - 48 ) - 24}{2 \cdot 4} : 3

The solutions to the quadratic equation are:

x = 9, x = 3

2 x^{2} - 7 x = - 1

7 x^{2} + 5 x = 0

- 12 x + x^{2} = - 35

s^{2} + 8 s + 32 = 0

3 (x)^{2} - 6 x + 9 = 0

What are the solutions to the equation (10-2x)(14-2x)=32 ?
The solutions to the equation (10-2x)(14-2x)=32 are x=9,x=3
Find the zeros of (10-2x)(14-2x)=32
The zeros of (10-2x)(14-2x)=32 are x=9,x=3