What are the solutions to the equation a^2-10a+24=0 ?

The solutions to the equation a^2-10a+24=0 are a=6,a=4

Find the zeros of a^2-10a+24=0

The zeros of a^2-10a+24=0 are a=6,a=4

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a^{2} - 10 a + 24 = 0

a = 6, a = 4

Solution steps

a^{2} - 10 a + 24 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

a_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

a = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

a = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

a = 6, a = 4

x, x^{2} + y^{2} - 2 x - 4 y + 5 = 0

x^{2} - 16 x = 60

4 x^{2} + 8 x - 60 = 0

7 x^{2} - 9 x - 10 = 0

2 x^{2} - 6 x

What are the solutions to the equation a^2-10a+24=0 ?
The solutions to the equation a^2-10a+24=0 are a=6,a=4
Find the zeros of a^2-10a+24=0
The zeros of a^2-10a+24=0 are a=6,a=4