What are the solutions to the equation 20^2+25^2=c^2 ?

The solutions to the equation 20^2+25^2=c^2 are c=5sqrt(41),c=-5sqrt(41)

Find the zeros of 20^2+25^2=c^2

The zeros of 20^2+25^2=c^2 are c=5sqrt(41),c=-5sqrt(41)

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2 0^{2} + 2 5^{2} = c^{2}

c = 541, c = - 541

Decimal Notation

c = 32.01562 \dots, c = - 32.01562 \dots

Solution steps

2 0^{2} + 2 5^{2} = c^{2}

Switch sides

c^{2} = 2 0^{2} + 2 5^{2}

Simplify

2 0^{2} + 2 5^{2} : 1025

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 1025, c = - 1025

1025 = 541

- 1025 = - 541

c = 541, c = - 541

(2 m - 1)^{2} - 4 = 14

(x + 6) (x + 5) = 2

8 y^{2} - 7 = 193

n^{2} - 18 = - 3 n

2 n^{2} + 5 n - 9 = 0

What are the solutions to the equation 20^2+25^2=c^2 ?
The solutions to the equation 20^2+25^2=c^2 are c=5sqrt(41),c=-5sqrt(41)
Find the zeros of 20^2+25^2=c^2
The zeros of 20^2+25^2=c^2 are c=5sqrt(41),c=-5sqrt(41)