What are the solutions to the equation 8x^2+27=0 ?

The solutions to the equation 8x^2+27=0 are x=(3sqrt(3))/(2sqrt(2))i,x=-(3sqrt(3))/(2sqrt(2))i

Find the zeros of 8x^2+27=0

The zeros of 8x^2+27=0 are x=(3sqrt(3))/(2sqrt(2))i,x=-(3sqrt(3))/(2sqrt(2))i

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8 x^{2} + 27 = 0

x = \frac{3 3}{2 2} i, x = - \frac{3 3}{2 2} i

Solution steps

8 x^{2} + 27 = 0

Move

27

to the right side

8 x^{2} = - 27

Divide both sides by

8

x^{2} = - \frac{27}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{27}{8}, x = - - \frac{27}{8}

- \frac{27}{8} = \frac{3 3}{2 2} i

- - \frac{27}{8} = - \frac{3 3}{2 2} i

x = \frac{3 3}{2 2} i, x = - \frac{3 3}{2 2} i

x, 3 y^{2} - 2 x^{2} = 6 - 2 x y

x, 6 (y - 2)^{2} + 3 (x + 5)^{2} - 4 x - 3 = 0

- 3 (x + 6)^{2} + 1 = 37

x^{2} + 8 x - 2 = 18

3 x^{2} + 26 x + 40 = 0

What are the solutions to the equation 8x^2+27=0 ?
The solutions to the equation 8x^2+27=0 are x=(3sqrt(3))/(2sqrt(2))i,x=-(3sqrt(3))/(2sqrt(2))i
Find the zeros of 8x^2+27=0
The zeros of 8x^2+27=0 are x=(3sqrt(3))/(2sqrt(2))i,x=-(3sqrt(3))/(2sqrt(2))i