What are the solutions to the equation x^2+8x-2=18 ?

The solutions to the equation x^2+8x-2=18 are x=2,x=-10

Find the zeros of x^2+8x-2=18

The zeros of x^2+8x-2=18 are x=2,x=-10

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x^{2} + 8 x - 2 = 18

x = 2, x = - 10

Solution steps

x^{2} + 8 x - 2 = 18

Move

18

to the left side

x^{2} + 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 \cdot 1}, x_{2} = \frac{- 8 - 12}{2 \cdot 1}

x = \frac{- 8 + 12}{2 \cdot 1} : 2

x = \frac{- 8 - 12}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 2, x = - 10

3 x^{2} + 26 x + 40 = 0

- 2 x^{2} + 20 x - 50 = 0

8 x^{2} + 2 x + 8 = 0

- 2 x^{2} + 7 = 2 x

x^{2} + 2 x + 26

What are the solutions to the equation x^2+8x-2=18 ?
The solutions to the equation x^2+8x-2=18 are x=2,x=-10
Find the zeros of x^2+8x-2=18
The zeros of x^2+8x-2=18 are x=2,x=-10