What are the solutions to the equation -3(x+6)^2+1=37 ?

The solutions to the equation -3(x+6)^2+1=37 are x=2sqrt(3)i-6,x=-2sqrt(3)i-6

Find the zeros of -3(x+6)^2+1=37

The zeros of -3(x+6)^2+1=37 are x=2sqrt(3)i-6,x=-2sqrt(3)i-6

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- 3 (x + 6)^{2} + 1 = 37

x = 23 i - 6, x = - 23 i - 6

Solution steps

- 3 (x + 6)^{2} + 1 = 37

Move

1

to the right side

- 3 (x + 6)^{2} = 36

Divide both sides by

- 3

(x + 6)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 6 = - 12 : x = 23 i - 6

Solve

x + 6 = - - 12 : x = - 23 i - 6

The solutions to the quadratic equation are:

x = 23 i - 6, x = - 23 i - 6

x^{2} + 8 x - 2 = 18

3 x^{2} + 26 x + 40 = 0

- 2 x^{2} + 20 x - 50 = 0

8 x^{2} + 2 x + 8 = 0

- 2 x^{2} + 7 = 2 x

What are the solutions to the equation -3(x+6)^2+1=37 ?
The solutions to the equation -3(x+6)^2+1=37 are x=2sqrt(3)i-6,x=-2sqrt(3)i-6
Find the zeros of -3(x+6)^2+1=37
The zeros of -3(x+6)^2+1=37 are x=2sqrt(3)i-6,x=-2sqrt(3)i-6