What are the solutions to the equation -2x^2+7=2x ?

The solutions to the equation -2x^2+7=2x are x=-(1+sqrt(15))/2 ,x=(sqrt(15)-1)/2

Find the zeros of -2x^2+7=2x

The zeros of -2x^2+7=2x are x=-(1+sqrt(15))/2 ,x=(sqrt(15)-1)/2

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- 2 x^{2} + 7 = 2 x

x = - \frac{1 + 15}{2}, x = \frac{15 - 1}{2}

Decimal Notation

x = - 2.43649 \dots, x = 1.43649 \dots

Solution steps

- 2 x^{2} + 7 = 2 x

Move

2 x

to the left side

- 2 x^{2} + 7 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

(- 2)^{2} - 4 (- 2) \cdot 7 = 215

x_{1, 2} = \frac{- ( - 2 ) \pm 2 15}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 15}{2 ( - 2 )}, x_{2} = \frac{- ( - 2 ) - 2 15}{2 ( - 2 )}

x = \frac{- ( - 2 ) + 2 15}{2 ( - 2 )} : - \frac{1 + 15}{2}

x = \frac{- ( - 2 ) - 2 15}{2 ( - 2 )} : \frac{15 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 15}{2}, x = \frac{15 - 1}{2}

x^{2} + 2 x + 26

8 m^{2} + m - 7 = 0

x^{2} + 4 x + 6 = 3

2 x^{2} + 8 x = 24

x^{2} + 8 x - 35 = 0

What are the solutions to the equation -2x^2+7=2x ?
The solutions to the equation -2x^2+7=2x are x=-(1+sqrt(15))/2 ,x=(sqrt(15)-1)/2
Find the zeros of -2x^2+7=2x
The zeros of -2x^2+7=2x are x=-(1+sqrt(15))/2 ,x=(sqrt(15)-1)/2