What are the solutions to the equation -2x^2+20x-50=0 ?

The solutions to the equation -2x^2+20x-50=0 are x=5

Find the zeros of -2x^2+20x-50=0

The zeros of -2x^2+20x-50=0 are x=5

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- 2 x^{2} + 20 x - 50 = 0

x = 5

Solution steps

- 2 x^{2} + 20 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 2 ) ( - 50 )}{2 ( - 2 )}

2 0^{2} - 4 (- 2) (- 50) = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 ( - 2 )}

x = \frac{- 20}{2 ( - 2 )}

\frac{- 20}{2 ( - 2 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

8 x^{2} + 2 x + 8 = 0

- 2 x^{2} + 7 = 2 x

x^{2} + 2 x + 26

8 m^{2} + m - 7 = 0

x^{2} + 4 x + 6 = 3

What are the solutions to the equation -2x^2+20x-50=0 ?
The solutions to the equation -2x^2+20x-50=0 are x=5
Find the zeros of -2x^2+20x-50=0
The zeros of -2x^2+20x-50=0 are x=5