What are the solutions to the equation 8m^2+m-7=0 ?

The solutions to the equation 8m^2+m-7=0 are m= 7/8 ,m=-1

Find the zeros of 8m^2+m-7=0

The zeros of 8m^2+m-7=0 are m= 7/8 ,m=-1

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8 m^{2} + m - 7 = 0

m = \frac{7}{8}, m = - 1

Decimal Notation

m = 0.875, m = - 1

Solution steps

8 m^{2} + m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 8 ( - 7 )}{2 \cdot 8}

1^{2} - 4 \cdot 8 (- 7) = 15

m_{1, 2} = \frac{- 1 \pm 15}{2 \cdot 8}

Separate the solutions

m_{1} = \frac{- 1 + 15}{2 \cdot 8}, m_{2} = \frac{- 1 - 15}{2 \cdot 8}

m = \frac{- 1 + 15}{2 \cdot 8} : \frac{7}{8}

m = \frac{- 1 - 15}{2 \cdot 8} : - 1

The solutions to the quadratic equation are:

m = \frac{7}{8}, m = - 1

x^{2} + 4 x + 6 = 3

2 x^{2} + 8 x = 24

x^{2} + 8 x - 35 = 0

8 x^{2} + 157 x - 60 = 0

3 x - 2 = x^{2}

What are the solutions to the equation 8m^2+m-7=0 ?
The solutions to the equation 8m^2+m-7=0 are m= 7/8 ,m=-1
Find the zeros of 8m^2+m-7=0
The zeros of 8m^2+m-7=0 are m= 7/8 ,m=-1