What are the solutions to the equation 2(x-1)^2=5 ?

The solutions to the equation 2(x-1)^2=5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1

Find the zeros of 2(x-1)^2=5

The zeros of 2(x-1)^2=5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1

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2 (x - 1)^{2} = 5

x = \frac{5}{2} + 1, x = - \frac{5}{2} + 1

Decimal

x = 2.58113 \dots, x = - 0.58113 \dots

Solution steps

2 (x - 1)^{2} = 5

Divide both sides by

2

(x - 1)^{2} = \frac{5}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{5}{2} : x = \frac{5}{2} + 1

Solve

x - 1 = - \frac{5}{2} : x = - \frac{5}{2} + 1

The solutions to the quadratic equation are:

x = \frac{5}{2} + 1, x = - \frac{5}{2} + 1

n^{2} - 10 n + 21 = 0

x^{2} + 12 x + 4 = 0

x^{2} + 11 x - 48 = 3 x

3 x^{2} - 9 x (2 x + 2) + 4 = 7

7^{2} + 1 1^{2} = c^{2}

What are the solutions to the equation 2(x-1)^2=5 ?
The solutions to the equation 2(x-1)^2=5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1
Find the zeros of 2(x-1)^2=5
The zeros of 2(x-1)^2=5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1