What are the solutions to the equation n^2-10n+21=0 ?

The solutions to the equation n^2-10n+21=0 are n=7,n=3

Find the zeros of n^2-10n+21=0

The zeros of n^2-10n+21=0 are n=7,n=3

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n^{2} - 10 n + 21 = 0

n = 7, n = 3

Solution steps

n^{2} - 10 n + 21 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

n_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, n_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

n = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

n = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

n = 7, n = 3

x^{2} + 12 x + 4 = 0

x^{2} + 11 x - 48 = 3 x

3 x^{2} - 9 x (2 x + 2) + 4 = 7

7^{2} + 1 1^{2} = c^{2}

(x - 6) (x + 1) = 0

What are the solutions to the equation n^2-10n+21=0 ?
The solutions to the equation n^2-10n+21=0 are n=7,n=3
Find the zeros of n^2-10n+21=0
The zeros of n^2-10n+21=0 are n=7,n=3