What are the solutions to the equation -8t^2+16t=0 ?

The solutions to the equation -8t^2+16t=0 are t=0,t=2

Find the zeros of -8t^2+16t=0

The zeros of -8t^2+16t=0 are t=0,t=2

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- 8 t^{2} + 16 t = 0

t = 0, t = 2

Solution steps

- 8 t^{2} + 16 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

1 6^{2} - 4 (- 8) \cdot 0 = 16

t_{1, 2} = \frac{- 16 \pm 16}{2 ( - 8 )}

Separate the solutions

t_{1} = \frac{- 16 + 16}{2 ( - 8 )}, t_{2} = \frac{- 16 - 16}{2 ( - 8 )}

t = \frac{- 16 + 16}{2 ( - 8 )} : 0

t = \frac{- 16 - 16}{2 ( - 8 )} : 2

The solutions to the quadratic equation are:

t = 0, t = 2

s, s^{2} - 2 s + 2 = 0

x^{2} - 16 x + 24 = 0

x, x^{2} = 25 k^{2} x

0 = 3 x^{2} + 6 x + 3

5 x^{2} + 10 x - 8 = 0

What are the solutions to the equation -8t^2+16t=0 ?
The solutions to the equation -8t^2+16t=0 are t=0,t=2
Find the zeros of -8t^2+16t=0
The zeros of -8t^2+16t=0 are t=0,t=2