What are the solutions to the equation 2x^2+12x-8=0 ?

The solutions to the equation 2x^2+12x-8=0 are x=-3+sqrt(13),x=-3-sqrt(13)

Find the zeros of 2x^2+12x-8=0

The zeros of 2x^2+12x-8=0 are x=-3+sqrt(13),x=-3-sqrt(13)

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2 x^{2} + 12 x - 8 = 0

x = - 3 + 13, x = - 3 - 13

Decimal Notation

x = 0.60555 \dots, x = - 6.60555 \dots

Solution steps

2 x^{2} + 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 8) = 413

x_{1, 2} = \frac{- 12 \pm 4 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 13}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 13}{2 \cdot 2}

x = \frac{- 12 + 4 13}{2 \cdot 2} : - 3 + 13

x = \frac{- 12 - 4 13}{2 \cdot 2} : - 3 - 13

The solutions to the quadratic equation are:

x = - 3 + 13, x = - 3 - 13

(2 m - 11) x^{2} - 3 (m + 4) x + (m - 3) = 0

3 x^{2} = - 6 - 8 x

11 x^{2} + 5 = 49

a, (a + b)^{2} = 49 + 12 b

h^{2} + 5 h = 155

What are the solutions to the equation 2x^2+12x-8=0 ?
The solutions to the equation 2x^2+12x-8=0 are x=-3+sqrt(13),x=-3-sqrt(13)
Find the zeros of 2x^2+12x-8=0
The zeros of 2x^2+12x-8=0 are x=-3+sqrt(13),x=-3-sqrt(13)