What are the solutions to the equation 25x^2-15x-64=5x-10 ?

The solutions to the equation 25x^2-15x-64=5x-10 are x=(2+sqrt(58))/5 ,x=(2-sqrt(58))/5

Find the zeros of 25x^2-15x-64=5x-10

The zeros of 25x^2-15x-64=5x-10 are x=(2+sqrt(58))/5 ,x=(2-sqrt(58))/5

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25 x^{2} - 15 x - 64 = 5 x - 10

x = \frac{2 + 58}{5}, x = \frac{2 - 58}{5}

Decimal Notation

x = 1.92315 \dots, x = - 1.12315 \dots

Solution steps

25 x^{2} - 15 x - 64 = 5 x - 10

Move

10

to the left side

25 x^{2} - 15 x - 54 = 5 x

Move

5 x

to the left side

25 x^{2} - 20 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 ( - 54 )}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 (- 54) = 1058

x_{1, 2} = \frac{- ( - 20 ) \pm 10 58}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 10 58}{2 \cdot 25}, x_{2} = \frac{- ( - 20 ) - 10 58}{2 \cdot 25}

x = \frac{- ( - 20 ) + 10 58}{2 \cdot 25} : \frac{2 + 58}{5}

x = \frac{- ( - 20 ) - 10 58}{2 \cdot 25} : \frac{2 - 58}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 58}{5}, x = \frac{2 - 58}{5}

4 w^{2} - 64 = 0

(x + 6) (x - 6) - 8 = 1 - 4 x

0 = 3 x^{2} + 8 x + 4

3 x^{2} + 8 x = 2 x - 9

s^{2} = 4

What are the solutions to the equation 25x^2-15x-64=5x-10 ?
The solutions to the equation 25x^2-15x-64=5x-10 are x=(2+sqrt(58))/5 ,x=(2-sqrt(58))/5
Find the zeros of 25x^2-15x-64=5x-10
The zeros of 25x^2-15x-64=5x-10 are x=(2+sqrt(58))/5 ,x=(2-sqrt(58))/5