What are the solutions to the equation n^2+5n+15=5-2n ?

The solutions to the equation n^2+5n+15=5-2n are n=-2,n=-5

Find the zeros of n^2+5n+15=5-2n

The zeros of n^2+5n+15=5-2n are n=-2,n=-5

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n^{2} + 5 n + 15 = 5 - 2 n

n = - 2, n = - 5

Solution steps

n^{2} + 5 n + 15 = 5 - 2 n

Move

2 n

to the left side

n^{2} + 7 n + 15 = 5

Move

5

to the left side

n^{2} + 7 n + 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

n_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 7 + 3}{2 \cdot 1}, n_{2} = \frac{- 7 - 3}{2 \cdot 1}

n = \frac{- 7 + 3}{2 \cdot 1} : - 2

n = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

n = - 2, n = - 5

a^{2} = 2 a x - x^{2}

9 n^{2} - 5 = - 99

n^{2} = 1

4 u^{2} + 9 = - 12 u

3 k^{2} + k - 1 = 0

What are the solutions to the equation n^2+5n+15=5-2n ?
The solutions to the equation n^2+5n+15=5-2n are n=-2,n=-5
Find the zeros of n^2+5n+15=5-2n
The zeros of n^2+5n+15=5-2n are n=-2,n=-5