What are the solutions to the equation (2x-3)^2=6 ?

The solutions to the equation (2x-3)^2=6 are x=(sqrt(6)+3)/2 ,x=(-sqrt(6)+3)/2

Find the zeros of (2x-3)^2=6

The zeros of (2x-3)^2=6 are x=(sqrt(6)+3)/2 ,x=(-sqrt(6)+3)/2

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(2 x - 3)^{2} = 6

x = \frac{6 + 3}{2}, x = \frac{- 6 + 3}{2}

Decimal Notation

x = 2.72474 \dots, x = 0.27525 \dots

Solution steps

(2 x - 3)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 6 : x = \frac{6 + 3}{2}

Solve

2 x - 3 = - 6 : x = \frac{- 6 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{6 + 3}{2}, x = \frac{- 6 + 3}{2}

(x + 2)^{2} = 3 x + 7

(x - 3) (x - 2) = 20

6 - 7 x = 3 x^{2}

n^{2} + 19 n + 66 = 6

w, m w^{2} = \frac{9 k \pm 41 k}{4}

What are the solutions to the equation (2x-3)^2=6 ?
The solutions to the equation (2x-3)^2=6 are x=(sqrt(6)+3)/2 ,x=(-sqrt(6)+3)/2
Find the zeros of (2x-3)^2=6
The zeros of (2x-3)^2=6 are x=(sqrt(6)+3)/2 ,x=(-sqrt(6)+3)/2